x=4/3 is zero of polynomial f(x)=6x^3-11x^2+kx -20 then k=?
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solution.
putting the value of x in equation.
=>6(4/3)^3 - 11 (4/3)^2+ k(4/3) - 20= 0
=> 2* 64/ 9 - 11* 16/9+ 4k/3 - 20=0
=> 128/9 - 176/9+ 4k/3 -20= 0
=> (128 - 176+ 12k - 180)/9= 0
=> -228+ 12k=0
=> 12k= 228
=> k= 19
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☺
putting the value of x in equation.
=>6(4/3)^3 - 11 (4/3)^2+ k(4/3) - 20= 0
=> 2* 64/ 9 - 11* 16/9+ 4k/3 - 20=0
=> 128/9 - 176/9+ 4k/3 -20= 0
=> (128 - 176+ 12k - 180)/9= 0
=> -228+ 12k=0
=> 12k= 228
=> k= 19
___________
☺
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