x^4-3x^2+4x-12 is divided by (x-3)
using remainder theoem
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Step-by-step explanation: p(x) = x3 – 2x2 – 4x – 1; g(x) = x + 1
Let g(x) = x + 1
x + 1 = 0
x = -1
P(-1) = (-1)3 – 2(-1)2 – 4(-1) – 1
= -1 -2 x 1 + 4 – 1
= -4 + 4 = 0
∴ Remainder = 0.
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