x^4+5x^2_36=0 solve
please solve this question
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Step-by-step explanation:
x^4+5x^2_36=0
=x^4+9x^2-4x^2-36=0
=x^2(x^2+9)-4(x^2+9)=0
=(x^2+9)(x^2-4)= 0
x^2+9=0 x^2-4=0
X^2= -9 x^= 4
x=√-9 x=+2 or x= -2
= +3i, -3i real roots
imaginary
roots
so x^4+5x^2_36=0, roots are +2,-2,3i,-3i
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