Question

x^4-5x^2+4=0 factorise it​

Answer 1

Step-by-step explanation:

${x}^{4} - {5x}^{2} = - 4$

$taking \: {x}^{2} common$

${x}^{2} ( {x}^{2} - 5) = - 4$

${x}^{2} = - 4 \: \: \: and \: ( {x}^{2} - 5) = - 4$

$x = 2 \: and \: \: {x}^{2} = 1$

So x= 2 and +1, -1

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