Question

X^4-5x+2x²+10x-8 divided by x²-2

Answer 1

Answer:

This is belong 's to maths.not hindi.

Answer 2

Answer:

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Explanation:

Answer:

The other zeroes of the polynomial are 1 and 4.

Step-by-step explanation:

The given polynomial is

p(x)=x^4-5x^3+2x^2+10x-8

It is given that -√2 and √2 are two zeroes. It means (x+\sqrt{2})\text{ and }(x-\sqrt{2}) are factors of p(x).

(x+\sqrt{2})(x-\sqrt{2})=x^2-2

Divide the polynomial by x^2-2, to find the remaining factors.

Using long division method, we get

\frac{x^4-5x^3+2x^2+10x-8}{x^2-2}=x^2-5x+4

Equate the quotient equal to 0, to find the remaining zeroes.

x^2-5x+4=0

x^2-4x-x+4=0

x(x-4)-1(x-4)=0

(x-4)(x-1)=0

x=4,1

Therefore other zeroes of the polynomial are 1 and 4.

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