Question

x^4-6x^3-26x^2+138x-35÷x^2-4x+1

Answer 1

here is ur answer

I hope it helps u

Answer 2

The two zeroes of the polynomial is 2+3,2−3

Therefore, (x−2+3)(x−2−3)=x2+4−4x−3

= x2−4x+1 is a factor of the given polynomial.

Using division algorithm, we get

x4−6x3−26x2+138x−35=(x2−4x+1)(x2−2x−35)

So, (x2−2x−35) is also a factor of the given polynomial.

x2−2x−35=x2−7x+5x−35

=x(x−7)+5(x−7)

=(x−7)(x+5)

Hence, 7 and −5are the other zeros of this polynomial.