Question

(x-4/7) - x = (5-x/3) + 1
value of x?

Answer 1

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$(x - \frac{4}{7} ) - x = (5 - \frac{x}{3}) + 1$

$\mapsto( \frac{7x - 4}{7} ) - x = ( \frac{15 - x}{3} ) + 1$

$\mapsto( \frac{7x - 4}{7} - x) = ( \frac{15 - x}{3} + 1)$

$\mapsto( \frac{7x - 4 - (7x)}{7} ) = ( \frac{15 - x + 3}{3} )$

$\mapsto( \frac{( - 4)}{7}) = ( \frac{12 - x}{3} )$

$\mapsto( - 4) \times 3 = 7(12 - x)$

$\mapsto( - 12) = 84 - 7x$

$\mapsto - 12 - 84 = - 7x$

$\mapsto - 96 = - 7x$

$\mapsto \: x = \frac{ - 96}{ - 7}$

$\mapsto \: x = \frac{96}{7}$

Answer 2

Answer:

• (x-4/7)-x=(5-x/3)+1
• (-x×x)-(-x+4/7)=(5×1-x/3)
• x-4/7=5-x/3
• x-4/7×3=5-x
• x-25/7=5-x
• x+x=3.57+5
• 2x=8.57
• X=8.57/2
• x=4.285