x=4 and y=2 is the solution of
the pair of linear equations.
a. x+y=6 , x-y=1
b.x+y=6, 2x+3y=9
c. x-y=2 , 2x+y=10
d. x+y=6 , x-y=-2
Answers
Answer:
c. x-y=2,2x+y=10
Step-by-step explanation:
x=4
y=2
x-y=2, 4-2=2
2x+y=10 , 2×4+2=10
8+2=10
Direct Answer:
Option C
Given:
★ The value of x and y as 4 and 2 respectively.
★ Four pairs of linear equations namely:
a. x + y = 6, x - y = 1
b. x + y = 6, 2x + 3y = 9
c. x - y = 2, 2x + y = 10
d. x + y = 6, x - y = -2
To Find:
Which pair of the given linear equations will have x = 4 and y = 2 as their solutions.
Solution:
In order to find the pair of linear equations with x = 4 and y = 2 as their solutions, we need to substitute the value of x and y with the given values and check whether the answer we get on solving is equal to the RHS.
Option a
No.1 x + y = 6
x = 4 , y = 2
Substituting the values into the LHS,
4 + 2 = 6
LHS = RHS.
No.2 x - y = 1
Substituting the values into the LHS,
4 - 2 = 2
2 ≠ 1
LHS ≠ RHS
The given values are not the solutions of the given pair of equations.
Option b
No.1 x + y = 6
Substituting the values into the LHS,
4 + 2 = 6
LHS = RHS.
No.2 2x + 3y = 9
Substituting the values into the LHS,
(2 x 4) + (3 x 2)
= 8 + 6 = 14
14 ≠ 9
LHS ≠ RHS
The given values are not the solutions of the given pair of equations.
Option c
No.1 x - y = 2
Substituting the values into the LHS,
4 - 2 = 2
LHS = RHS
No.2 2x + y = 10
Substituting the values into the LHS,
(2 x 4) + 2
= 8 + 2 = 10
LHS = RHS
The given values are the solutions of the given pair of equations.
Option d
No.1 x + y = 6
Substituting the values into the LHS,
4 + 2 = 6
LHS = RHS
No.2 x - y = -2
Substituting the values into the LHS,
4 - 2 = 2
LHS ≠ RHS
The given values are not the solutions of the given pair of equations.
From the above observations, we can conclude that Option C is the pair of linear equations that has the given values of x and y as the solution.
a. x + y = 6, x - y = 1
b. x + y = 6, 2x + 3y = 9
c. x - y = 2, 2x + y = 10 ✔
d. x + y = 6, x - y = -2