Question

X^4+ax^3+bx^2-32x+16=0 has all positive roots then

Answer 1

$x( {x3 +ax }^{2} + bx - 32 ) = - 16 \\ {x3 + a {x }^{2} } + bx - 16 = 0 \\ x(x {}^{2} + ax + b - 16) = 0 \\ {x }^{2} + ax + b = 0$
what is the real question???i could not understand it..sry