Question

(x+4)whole square +(x-4)whole square =2x(x-5)+8



This is my question from chapter : Linear Equations in One Variable....
Please answer fast​

Answer 1

Answer:

$(x+4)^{2}$ + $(x-4)^{2}$ = 2x(x+5) + 8

⇒ ( $x^{2}$ + 8 ) + ( $x^{2}$ - 8 ) = $2x^{2}$ + 10x + 8

⇒ $2x^{2}$ - $2x^{2}$ - 10x = 8

⇒ -10x = 8

⇒ x = $\frac{8}{-10}$

⇒ x = $\frac{-4}{5}$

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Answer 2

Answer:

the President is the answer

Step-by-step explanation:

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