Math, asked by tanmaykamath76, 9 months ago

(x-4)(x+2) =0 by factorization method

Answers

Answered by RishikaPaul334
1

Answer:

(x - 4)(x + 2) = 0

x(x + 2) - 4(x + 2) = 0

x {}^{2}  + 2x - 4x  - 8 = 0

x {}^{2}   - 2x - 8 = 0

Answered by gnagamokshi
0

Answer:

x=4,-2

Step-by-step explanation:

x-4*x+2=0

x^2+2x-4x-8=0

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

x-4=0;x+2=0

x=4;x=-2

x=4,-2

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