Question

x^4+x^2+1=0 solve it​

Answer 1

Step-by-step explanation:

x^4 + x^2 +1 =0

Let x^2 =a

So, the above equation can be written as

a^2 + a +1=0

→D = a^2- 4a^2 = -5a^2 .

Since , the discriminant is coming negative .

→x^2 is also a negative number which is impossible for any real number .

→The value of x is not existing .

Answer 2

Answer:

sorry i dont know