Question

x^4+x^2=1 then what is the value of x?​

Answer 1

Answer:

Step-by-step explanation:

LET x²=y

y²+y=1

y²+y-1=0

y = -b±√(b²-4ac) / 2a

Δ=b²-4ac=1²-4(1)(-1)=1+4=5

y=-1±√5 / 2

y = -1+√5 /2 or -1-√5 /2

x = √[-1+√5 / 2] or √[-1-√5 / 2]

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