x^4-(x-2)^4
Factorise
I will mark the first answer(correct) as brainliest
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Answer:
8(x³-3x²+4x-2)
Step-by-step explanation:
x⁴-(x-2)² = x⁴- {(x-2)(x-2)}²
= x⁴ - {x(x-2)-2(x-2)}
= x⁴ - (x²-2x-2x+4)²
= x⁴ - (x²-4x+4)²
= x⁴ - {x²(x²-4x+4)-4x(x²-4x+4)+4(x²-4x+4)
= x⁴-(x⁴-4x³+4x²-4x³+16x²-16x+4x²-16x+16)
= x⁴-x⁴+4x³-4x²+4x³-16x²+16x-4x²+16x-16
= 8x³ - 24x² + 32x - 16
= 8( x³-3x² + 4x - 2)
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