x/4-x/2+x/3
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Answers
Step-by-step explanation:
Given, (x−2) , (x+3) and (x−4) are factors of polynomial x
3
−3x
2
−10x+24.
Then, f(x)=x
3
−3x
2
−10x+24.
If (x−2) is a factor, then x−2=0⟹x=2.
Replace x by 2, we get,
f(2)=(2)
3
−3(2)
2
−10(2)+24
f(2)=8−12−20+24
f(2)=0.
The value of f(2) is zero.
Then (x−2) is the factor of the polynomial x
3
−3x
2
−10x+24.
If (x+3) is factor, then x+3=0⟹x=−3.
Replace x by −3, we get,
f(−3)=(−3)
3
−3(−3)
2
−10(−3)+24
f(−3)=−27−27+30+24
f(−3)=0.
The value of f(−3) is zero.
Then (x+3) is the factor of the polynomial x
3
−3x
2
−10x+24.
If (x−4) is factor, then x−4=0⟹x=4.
Replace x by 4, we get,
f(4)=(4)
3
−3(4)
2
−10(4)+24
f(4)=64−48−40+24
f(4)=0.
The value of f(4) is zero.
Then (x+4) is the factor of the polynomial x
3
−3x
2
−10x+24.
Therefore, hence showed that (x−2) , (x+3) and (x−4) are factors of polynomial x
3
−3x
2
−10x+24.
answer is in the image
and the Alternate answer is
= 0.0833333 x
