Question

(x-4)(x-2)=x²-8 this is in error correct it​

Answer 1

Answer: x² -6x + 8

(x-4)(x-2) can also be written as (x + {-4})(x + {-2})

Now it is in the form of (x+a)(x+b)

Using identity (x+a)(x+b) = x² + (a+b)x + ab

We get

x² + (-4 + -2)x + (-4 x -2)

= x² + (-6x) + (8)

= x² -6x + 8

which is the correct answer.

Hope it helps you :)

Answer 2

Answer:

$(x - 4)(x - 2)$ $=x^2 - 6x + 8$

In order to correct the error, we need to add (16 - 6x) to the erratic result $(x^2 - 8)$.

Step-by-step explanation:

$(x - 4)(x - 2)$

$=x(x - 2) - 4(x - 2)$

$=x^2 - 2x - 4x + 8$

$=x^2 - 6x + 8$

In order to correct the error, we need to add (16 - 6x) to the erratic result $(x^2 - 8)$.