Question

x^4+x^3-7x^2-x+6 factor the following by division​

Answer 1

Answer:

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Step-by-step explanation:

see the answer in the attachment hope it will help you

Answer 2

Answer: Hope Its Helps

Step-by-step explanation:

f(x) = x^4+x^3-7x^2-x+6  

f(x) = x^3(x+1) - (7x^2+ x -6)

f(x) = x^3(x+1) - (7x^2+ 7x-6x -6)

f(x) = x^3(x+1) - (7x-6)(x+1)

f(x) = (x+1) (x^3-7x+6)

 

By using remainder theorem for (x^3-7x+6)

f(1) = 1-7+6 = 0 Hence(x-1) is a factor of (x^3-7x+6)

Hence using long division method, we can get that f(x) =(x+1)(x-1)(x^2+x-6)

 

f(x) = (x+1) (x-1)(x^2+x-6)

f(x) = (x+1) (x-1) (x+3)(x-2)