Math, asked by nishant3554, 1 year ago

(x-4)(x-3)(x-2)(x-1)=120

Answers

Answered by Gurveer08

HOPE IT HELPS YOU MATE....

Attachments:

anantjaiswal1978: This is may right but I think that's answer is -5 because of

anantjaiswal1978: Let x be common

anantjaiswal1978: x(-4*(-3)*(-2)*(-1))=120. x(-12*-2)=120. x(-24)=120. x=120/-24. x= -5

Answered by rashedctg

Answer:

Step-by-step explanation:

(x-4)(x-3)(x-2)(x-1)= 120

Or, (x-4)(x-1)(x-3)(x-2) = 120

Or, (x^2-5x+4)(x^2-5x+6) = 120

Or, (p+4)(p+6)=120 [let, x^2-5x=P]

Or, p^2+10p+24-120= 0

Or, p^2+10p-96= 0

Or, p^2+16p-6p-96= 0.

Or, (p+16)(p-6)= 0

So, p+16= 0

Or, p= -16

Value of p is negetive. So it is avoided.

And

p-6= 0

Or, p=6

Now,

P=6

Or, x^2-5x-6= 0

Or, x^2-6x+x-6=0

Or, (x-6) (x+1)= 0

So, x= 6 and -1

Previous Question

Next Question