Question

x-(4-x)=3(x-4)-4 find the value of x​

Answer 1

Answer:

$x-(4-x)=3(x-4)-4$

$x - 4 + x = 3x - 12 - 4$

$3x = 12$

$x = 4$

Answer 2

tep 1: Simplify both sides of the equation.

x−(4−x)=3(x−4)−4

x+−1(4−x)=3(x−4)−4(Distribute the Negative Sign)

x+(−1)(4)+−1(−x)=3(x−4)−4

x+−4+x=3(x−4)−4

x+−4+x=(3)(x)+(3)(−4)+−4(Distribute)

x+−4+x=3x+−12+−4

(x+x)+(−4)=(3x)+(−12+−4)(Combine Like Terms)

2x+−4=3x+−16

2x−4=3x−16

Step 2: Subtract 3x from both sides.

2x−4−3x=3x−16−3x

−x−4=−16

Step 3: Add 4 to both sides.

−x−4+4=−16+4

−x=−12

Step 4: Divide both sides by -1.

-x/-1 = -12 / -1

X= 12