Question

x/4+x-5/3=10
$\binom{x}{4} + \binom{x + 5}{3} =10$
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Answer 1

Step-by-step explanation:

Above equation

$\frac{5x}{4} = \frac{35}{3} \: \: or \: x = \frac{28}{3}$

below

$\frac{x(x - 1)(x - 2)(x - 3)}{4.3.2.1} + \frac{( x + 5)(x + 4)(x + 3) }{3.2.1 } = 10 \\ \\ \\ \frac{1}{6} (\frac{x(x - 1)(x - 2)(x - 3)}{4} + \frac{( x + 5)(x + 4)(x + 3) }{1 } ) = 10$

observe that constant term is going to be zero so one root is x = 0 .

Answer 2

Answer:

x/4 + (x-5)/3 = 10

(3x+4(x-5)/12=10

(3x+4x-20)/12=10

(7x-20)=10*12

(7x) = 120 +20

(7x)=140

x =    140/7

x =  20

Step-by-step explanation: