Question

(x+4)(x+5)(x+1)(x+1)=0​

Answer 1

Answer:

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(x)(x+4)(x+5)(x+1)(x+1)=0

Let (x-1/x)=y

4y2-4y+1=0

4y2-2y-2y+1=0

2y(2y-1)-1(2y-1)=0

therefore,(2y-1)(2y-1)=0

hence y=1/2

putting value of y

x-1/x=1/2                                      [by cross multiplication]

2x-2=x

2x-x=2

x=2

Hence found.     :)

Answer 2

Answer:

x^4+20=0

x^4=-20

x=2√2

Step-by-step explanation:

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