Question

x/4+y/3=-1/12 x/2-5/4y=7/4 by elimination method x/4+y/3=-1/12 x/2-5/4y=7/4 by elimination method .

Answer 1

Step-by-step explanation:

x/4+y/3=-1/12

(Multiplying both sides by 12)

3x+4y=-1...(1)

x/2-5/4y=7/4

(Multiplying both sides by 4)

2x-5/y=7...(2)

(Multiply eq(1) by 2)

6x+8y=-2...(3)

(Multiply eq(2) by 3)

6x+15/y=21...(4)

(Subract equation(3) from equation(4) )

6x+15/y=21

-

6x+8y=-2

we get,

15/y-8y=23

(Multiply both the sides by y)

15-8y^2=23y

-8y-23y+15=0 .

Here,a=-8,b=-23,c=15.

y=[-b+root(b^2-4ac)]/2a or

[-b-root(b^2-4ac)]/2a

Answer 2

Step-by-step explanation:

x/4+y/3=-1/12 x/2-5/4y=7/4 by elimination method x/4+y/3=-1/12 x/2-5/4y=7/4 by elimination method .