Question

x^4-y^4+x^2-y^2 factorise to the following polynomials​

Answer 1

Answer:

Step-by-step explanation:

Answer:

x^{4}-y^{4}+x^{2}-y^{2}\\=(x+y)(x-y)[(x^{2}+y^{2}+1]

Step-by-step explanation:

x^{4}-y^{4}+x^{2}-y^{2}\\=[(x^{2})^{2}-(y^{2})^{2})]+x^{2}-y^{2}\\=(x^{2}+y^{2})(x^{2}-y^{2})+x^{2}-y^{2}

\* By algebraic identity :

\boxed {a^{2}-b^{2}=(a+b)(a-b)} *\

=(x^{2}-y^{2})[(x^{2}+y^{2}+1]

=(x+y)(x-y)[(x^{2}+y^{2}+1]

Therefore,

x^{4}-y^{4}+x^{2}-y^{2}\\=(x+y)(x-y)[(x^{2}+y^{2}+1]

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