Question

X^40+2 is divided by x^4+1. what is the remainder

Answer 1

Answer:

3

Step-by-step explanation:

We are given that

p(x) = x^40 + 2 and g(x) = x^4 + 1

Now, x^40 + 2 = (x^4)^10 + 2 .... (1)

x^4 + 1 = 0 so x^4 = -1 ....(2)

put (2) in (1), we get

(x^4)^10 + 2 = (-1)^10 + 2 = 1 + 2 = 3

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