Math, asked by Anonymous, 1 day ago

❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ
❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ
❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​

Attachments:

Answers

Answered by Sahan677
7

\lim_{x \to 1} \frac{2 x - 7}{4 x + 5}

Substitute the variable with the value:

\color{red}{\lim_{x \to 1} \frac{2 x - 7}{4 x + 5}} = \color{red}{\left(- \frac{5}{9}\right)}

Therefore,

\lim_{x \to 1} \frac{2 x - 7}{4 x + 5} = - \frac{5}{9}

Answer:

\lim_{x \to 1} \frac{2 x - 7}{4 x + 5}=- \frac{5}{9}

Similar questions