Math, asked by Anonymous, 1 month ago


❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ
❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ
❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​

Attachments:

Answers

Answered by naveenprasad10a
0

∫20∫4−2x0(8−3x−2y−(3x+y−4))dydx.

Note how we can rewrite the integrand as an integral, much as we did in Section 14.1:

8−3x−2y−(3x+y−4)=∫8−3x−2y3x+y−4dz.

Thus we can rewrite the double integral that finds volume as

∫20∫4−2x0(8−3x−2y−(3x+y−4))dydx=∫20∫4−2x0(∫8−3x−2y3x+y−4dz)dydx

Similar questions