Math, asked by SAVIVERMA1208, 1 year ago

X^4dy+dx+x^3y+cosec(xy)=0 solution of the differential equation

Answers

Answered by knjroopa
37

Answer:

2 cos + x^-2

Step-by-step explanation:

Given X^4dy/dx+x^3y+cosec(xy)=0 solution of the differential equation

We have x^4 dy + x^3 y dx + cosec (xy) dx = 0

           x^3(y dx + x dy) + cosec(xy) dx = 0

          dx / x^3 + d(xy) / cosec xy = 0

Integrating the above equation we have

     ∫dx / x^3 + ∫d(xy) / cosec(xy) = 0

  ∫x ^-3 dx + ∫d(xy)/cosec(xy) = 0

∫x^-3 dx + ∫ sin xy d(xy)

1/-2 x^-2 - cos xy

2 cos xy + x^-2 = c

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