X^4dy+dx+x^3y+cosec(xy)=0 solution of the differential equation
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Answer:
2 cos + x^-2
Step-by-step explanation:
Given X^4dy/dx+x^3y+cosec(xy)=0 solution of the differential equation
We have x^4 dy + x^3 y dx + cosec (xy) dx = 0
x^3(y dx + x dy) + cosec(xy) dx = 0
dx / x^3 + d(xy) / cosec xy = 0
Integrating the above equation we have
∫dx / x^3 + ∫d(xy) / cosec(xy) = 0
∫x ^-3 dx + ∫d(xy)/cosec(xy) = 0
∫x^-3 dx + ∫ sin xy d(xy)
1/-2 x^-2 - cos xy
2 cos xy + x^-2 = c
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