Question

x+4y =10 and 2x-2y =2​

Answer 1

x+4y =10 ........1

2x-2y =2.........2

form eq1

x= 10-4y

2x-2y =2

divide eq2 by 2

x-y = 1 ...........3

put x in eq3

10-4y -y = 1

-5y = 1-10

-5y = -9

y= 9/5

put y in x

x= 10-4× 9/5

x= 10 - 36 /5

x= 50 -36 /5

x= 14 /5

Answer 2

Given

$\sf\pink{⟶}$ Equation

• x + 4y = 10....(i)
• 2x - 2y = 2

Solution

$\sf\pink{⟶}$ Second equation can be written as

• x - y = 1....(ii)

From (i) and (ii), we get

[By substitution method]

$\tt:\implies{x + 4y = 10}$

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$\tt:\implies{x = 10 - 4y}$

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Putting the value of x in Equation (ii),

$\tt:\implies{(10 - 4y) - y = 1}$

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$\tt:\implies{-4y - y = 1 - 10}$

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$\tt:\implies{\cancel{-}5y = \cancel{-}9}$

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$\tt:\implies{y = \dfrac{9}{5}}$

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Substituting the value of y in equation (i)

$\tt:\implies{\dfrac{9}{5} + 4x = 10}$

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$\tt:\implies{4x = \dfrac{10 \times 5}{9}}$

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$\tt:\implies{4x = \dfrac{50}{9}}$

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$\tt:\implies{x = \dfrac{\cancel{50}}{9 \times \cancel{4}}}$

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$\tt:\implies{x = \dfrac{25}{18}}$

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$\sf\pink{⟶}$ The values of

• x = $\dfrac{25}{18}$

• y = $\dfrac{9}{5}$

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