X-4y+14=0 and 3x+xy-14 =0. Solve it by alimination method
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Answer:
x = 2, y = 4
Step-by-step explanation:
Given equations are
x - 4y + 14 = 0 ---------(1)
3x + 2y - 14 = 0 ---------(2)
By Cancellation Method :
Now do like this
eqn(1)*(1)=> x - 4y + 14 = 0
eqn(2)*(2)=> 6x + 4y -28 = 0
---------------------------
7x - 14 = 0
--------------------------
=> 7x = 14
=> x = 14/7
=> x = 2
Therefore x = 2
Now substitute x = 2 in x - 4y + 14 =0
=> 2 - 4y + 14 =0
=> 4y = 16
=> y = 16/4
=> y = 4
Therefore y = 4
The values of x = 2,y = 4
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thank you.
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