Question

X+4y=16,2x-3y=1 simultaneous equation

Answer 1

Answer:

$multiplying \: equation1 \: by \: 2 \\ 2x + 8y = 32 \: \: \: eq3 \\ adding \: eq \: 2 \: and \: 3 \\ 2x + 8y = 32 \\ + 2x - 3y = 1 \\ 5y = 30 \\ y = 30 \div 5 \\ y = 6 \: \\ putting \: y = 6 \: in \: eq \: 1 \\ x + 4y = 16 \\ x + 4 = 16 \\ x = 16 - 4 \\ x = 12$

it is correct answer..