Math, asked by RudrakshaBhute, 1 day ago

(x+4y)²- 16y² factories the following by splitting the middle term or by using identity ​

Answers

Answered by IIMidnightHunterII
3

\maltese\LARGE\textsf{\underline{ SoLuTioN :-}}

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{( x + 4y )² - ( 16y )²}

\large\textsf{                                                               }

By using the formula:-

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{purple}{a² - b² = ( a + b )( a - b )}}

\large\textsf{                                                               }

Here :-

  • a = x + 4y
  • b = 16y

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{[ ( x + 4y ) + ( 16y ) ] × [(x + 4y ) - ( 16y ) ]}

\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{( x + 20y )( x - 12y )}}

\large\textsf{                                                               }

Algebraic Formulas :-

\large\textsf{                                                               }

\qquad\tt{:}\longrightarrow\large\textsf{( a + b )² = a² + b² + 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{( a - b )² = a² + b² - 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{a² - b² = ( a + b ) ( a - b )}

\qquad\tt{:}\longrightarrow\large\textsf{a² + b² = ( a + b )² - 2ab}

\qquad\tt{:}\longrightarrow\large\textsf{a³ + b³ = ( a + b ) ( a² - 2ab + b² )}

\qquad\tt{:}\longrightarrow\large\textsf{a³ - b³ = ( a - b ) ( a² + ab + b² )}

\qquad\tt{:}\longrightarrow\large\textsf{( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac }

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