[ x+4y ]^3 write the cubes in expanded form
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Using identity
( a+b)³ = a³+b³ +3ab (a+b)
Here, a = x and b = 4y
:.
(x+4y)³ = x³ + (4y)³ + 3(x)(4y)(x+4y)
= x³ + 64y³ + 12xy(x+4y)
= x³ + 64y³ + 12x²y + 48xy²
Hope you got it !!
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