Math, asked by ayyanbudye1, 4 months ago

x+4y=(-4);3y-5x=-1
Solve the equation ​

Answers

Answered by jhas75070
0

Step-by-step explanation:

The value of x and y are -\frac{8}{23}−

23

8

and -\frac{21}{23}−

23

21

.

Step-by-step explanation:

The equations are:

\begin{gathered}x+4y=-4...(i)\\3y-5x=-1...(ii)\end{gathered}

x+4y=−4...(i)

3y−5x=−1...(ii)

Fro equation (i) the value of x is:

x=-4-4yx=−4−4y

Substitute the value of x in (ii) and solve for y as follows:

\begin{gathered}3y-5x=-1\\3y-5(-4-4y)=-1\\3y+20+20y=-1\\23y=-21\\y=-\frac{21}{23}\end{gathered}

3y−5x=−1

3y−5(−4−4y)=−1

3y+20+20y=−1

23y=−21

y=−

23

21

Substitute y in x=-4-4yx=−4−4y and solve for x as follows:

\begin{gathered}x=-4-4y\\=-4-(4\times -\frac{21}{23})\\=-4+\frac{84}{23}\\=-\frac{8}{23}\end{gathered}

x=−4−4y

=−4−(4×−

23

21

)

=−4+

23

84

=−

23

8

Answered by raviathira758
0

Step-by-step explanation:

Rearranging 2x+y=−4

−5x+3y=−1

By using elimination method

3(2x+y)=−4×3

−5x+3y=−1

⇒ 6x+3y=−12

−5x+3y=−1

----------------------  → sign reverses for subtraction

           x=−11

⇒ y−4−2x=0;y=18

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