x= √( √ 5+1)/( √ 5-1) show that x^2-x-1=0
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X=√√{(5+1)/(√5−1)}
=√{(√5+1)(√5+1)/(√5+1)(√5–1)} (multiply by (√5+1)
=√{(√5+1)^2/4}
=(√5+1)/2.
then the keep value of x in equation x square - x - 1 = 0
=√{(√5+1)(√5+1)/(√5+1)(√5–1)} (multiply by (√5+1)
=√{(√5+1)^2/4}
=(√5+1)/2.
then the keep value of x in equation x square - x - 1 = 0
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