Question

x+5=12, xy=40 find x2 and y2​

Answer 1

Answer:

question is wrongly written.

(x+y)² = x²+y² + 2xy

(12)² = x²+y² +2*40

144-80 = x²+y²

x²+y² = 64 ( If you wanna know this ) .

Rest values not possible in Positive integers ...

$\boxed{Mark\: as\: Brainlist}$

Answer 2

Answer:

x + 5 = 12, x=12-5 = 7

xy=40,7Xy=40, y=40/7

x2 = 7^2 = 49

y2 = (40/7) 2=1600/49