Question

(x+5)2=2 (5x-3) find the discriminant
Of the quadratic equation

Answer 1

Answer :

Discreminant (D)=-124

Explanation:

(x+5)² = 2(5x-3)

=> x²+2*x*5+5²=10x-6

=> x²+10x+25-10x+6=0

=> x²+31=0

Compare x²+0+31=0 with

ax²+bx+c=0, we get

a=1 , b = 0 , c = 31

discreminant (D)=b²-4ac

= 0² - 4×1×31

= -124

Therefore,

D = -124

••••

Answer 2

Answer:

-124

Step-by-step explanation:

Here, the given equation,

$(x+5)^2=2(5x-3)$

$x^2+10x+25=10x-6$

$x^2+10x+25-10x+6=0$

$x^2+0x+31=0$     ( By combining like terms )

We know that, the discriminant of a quadratic equation $ax^2+bx+c=0$ is,

$D=b^2-4ac$

By comparing,

The discriminant of the given quadratic equation is,

$D=0^2-4\times 1\times 31$

$=0-124$

$=-124$