Question

(x+5)^2 -4(x+5) factozise and answer is 7(2x-3)​

Answer 1

x+2

x+3

=

2x−3

3x−7

(x + 3)(2x - 3) = (3x - 7)(x + 2)(x+3)(2x−3)=(3x−7)(x+2)

2 {x}^{2} - 3x + 6x - 9 = 3 {x}^{2} + 6x - 7x - 142x

2

−3x+6x−9=3x

2

+6x−7x−14

2 {x}^{2} - 3 {x}^{2} + 3x - 9 = - x - 142x

2

−3x

2

+3x−9=−x−14

- {x}^{2} + 3x - 9 + x + 14 = 0−x

2

+3x−9+x+14=0

- {x}^{2} + 4x + 5 = 0−x

2

+4x+5=0

- ( {x}^{2} - 4x - 5) = 0−(x

2

−4x−5)=0

{x}^{2} - 4x - 5 = 0x

2

−4x−5=0

{x}^{2} - (5 - 1)x - 5 = 0x

2

−(5−1)x−5=0

{x}^{2} - 5x + x - 5 = 0x

2

−5x+x−5=0

x(x - 5) + 1(x - 5) = 0x(x−5)+1(x−5)=0

(x - 5)(x + 1) = 0(x−5)(x+1)=0

Either, x-5=0 => x = 5

Or, x+1=0 => x = -1.

The values of x are 5 and -1

Step-by-step explanation:

Hope it helps ❄️

Answer 2

Step-by-step explanation:

You only said the answer no