Question

(x+5)^2-4(x+5) solve please​

Answer 1

${(x + 5)}^{2} - 4(x + 5)$

$= {x}^{2} + 10x + 25 - 4x - 20$

$= {x}^{2} + 6x + 5$

Answer 2

Answer:

Here's your answer

#HAPPY FRIENDSHIP DAY ❤

${x}^{2} + 25 + 10x - 4x - 20 = 0 \\ \\ {x}^{2} + 6x + 5 = 0 \\ \\ {x}^{2} + 5x + x + 5 = 0 \\ \\ \\ x(x + 5) + 1(x + 5) = 0 \\ \\ (x + 5)(x + 1) = 0$

Hope it helps ✌