Question

x=√5+2 எ‌னி‌ல் x〗^2+1/x^2 இ‌ன் ம‌தி‌ப்பை‌‌க் கா‌ண்க

Answer 1

Answer:

sorry i dont know the language

Answer 2

$x^{2}+\frac{1}{x^{2}}=18$

விளக்கம்:

$x=\sqrt{5}+2$

$\frac{1}{x}=\frac{1}{\sqrt{5}+2}$

$\frac{1}{x}=\frac{1}{\sqrt{5}+2} \times \frac{\sqrt{5}-2}{\sqrt{5}-2}$

$=\frac{\sqrt{5}-2}{5-4}=\frac{\sqrt{5}-2}{1}$

$=\sqrt{5}-2$

$x^{2}+\frac{1}{x^{2}}=\left(x+\frac{1}{x}\right)^{2}-2$

$=[\sqrt{5}+2+\sqrt{5}-2]^{2}-2$

$=(2 \sqrt{5})^{2}-2$

$=4(5)-2$

= 20 - 2

= 18

$x^{2}+\frac{1}{x^{2}}=18$