Question

(x-5)2- (x+2)2 = -2 solve it​

Answer 1

Answer:

Step-by-step explanation:

2(x-5)-2(x+2)

2x-10 -2x-4

-10-4

=-14

we see LHS is not equal to RHS

Answer 2

Given: The equation is$(x-5)^{2} -(x+2)^{2} =-2$.

We have to solve the above equation.

As we know that:

$A.(a+b)^{2} =a^{2} +2ab+b^{2} \\\\B.(a-b)^{2}= a^{2} -2ab+b^{2}$

We are solving in the following way:

We have,

$(x-5)^{2} -(x+2)^{2} =-2$

From the above identities, we can write:

$=>x^{2} -10x+25-x^{2} -4x-4=-2\\=>-14x+1=-2\\=>-14=-2-1\\=>14x=-3\\=>x=\frac{-3}{14} \\=>x=-0.214$

Hence, the value of $x$ will be$-0.214$.