Question

x-5/2-x-3/5=1/5 find the value of x​

Answer 1

$\huge{\pink{\underline{\sf{AnSweR:}}}}$

Given,

$→\;{\sf{\frac{x-5}{2}-\frac{x-3}{5} = \frac{1}{5}}}$

The LCM of 5,2 is 10.

$→\;\Large{\sf{\frac{5(x-5)}{5(2)}-\frac{2(x-3)}{2(5)} = \frac{1}{5}}}$

$→\;\Large{\sf{\frac{5x-25}{10}-\frac{2x-6}{10} = \frac{1}{5}}}$

$→\;\Large{\sf{\frac{5x-25-2x+6}{10} = \frac{1}{5}}}$

$→\;\Large{\sf{3x-19 = \frac{10}{5}}}$

$→\;\Large{\sf{3x = 2+19}}$

$→\;\Large{\sf{x = \frac{21}{3}}}$

$→\;{\bf{x = 7}}$

Therefore, The Value of x is $\fbox\red{7}$

Hope It Helps You ✌️

Answer 2

Step-by-step explanation:

AnSweR:

Given,

→\;{\sf{\frac{x-5}{2}-\frac{x-3}{5} = \frac{1}{5}}}→2x−5−5x−3=51

The LCM of 5,2 is 10.

→\;\Large{\sf{\frac{5(x-5)}{5(2)}-\frac{2(x-3)}{2(5)} = \frac{1}{5}}}→5(2)5(x−5)−2(5)2(x−3)=51

→\;\Large{\sf{\frac{5x-25}{10}-\frac{2x-6}{10} = \frac{1}{5}}}→105x−25−102x−6=51

→\;\Large{\sf{\frac{5x-25-2x+6}{10} = \frac{1}{5}}}→105x−25−2x+6=51

→\;{\sf{3x-19 = \frac{10}{5}}}→3x−19=510

→\;{\sf{3x = 2+19}}→3x=2+19

→\;{\sf{x = \frac{21}{3}}}→x=321

→\;{\bf{x = 7}}→x=7