Question

x-5/2-x-3/6+x/6=3/2 find the x​

Answer 1

Here is your Answer:

$\frac{x-5}{2} -\frac{x-3}{6} +\frac{x}{6}=\frac{3}{2}$

$\frac{3(x-5)-(x-3)+x}{6} =\frac{3}{2}$

$\frac{3(x-5)-(x-3)+x}{3} =3$

$3x-15-x+3+x=9$

$3x-15+3=9$

$3x-12-9=0$

$3x-21=0$

$3x=21$

$x=\frac{21}{3}$

$x=7$

Hope it helps

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