Question

(x - 5)² + (y + 1)² = 0, find the value of x² + y²​

Answer 1

Answer:

any square numbers is always +ve.

so (x-5)² ≥0

and

(y+1)² ≥ 0

so (x - 5)² + (y + 1)² = 0

only when

x-5 = 0

and y+1 = 0

so x= 5 and y= -1

x²+y² = 5² + (-1)² = 26

Answer 2

EXPLANATION.

⇒ (x - 5)² + (y + 1)² = 0.

As we know that,

The square of a number is ≥ 0.

⇒ (x - 5)² = 0.

⇒ x - 5 = 0.

⇒ x = 5.

⇒ (y + 1)² = 0.

⇒ y + 1 = 0.

⇒ y = - 1.

To find :

value of : x² + y².

⇒ x² + y² = (5)² + (-1)².

⇒ x² + y² = 25 + 1 = 26.