Question

x= √5+√3/√5-√3 and y=√5-√3/√5+√3 find value x and y

Answer 1

x = 4 + √15
y = 4 - √15
please rationalise and after that you get ur answer

Answer 2

Hey friend,
Here is the answer you were looking for:
$x = \frac{ (\sqrt{5}) + ( \sqrt{3}) }{( \sqrt{5}) - ( \sqrt{3} ) } \\ on \: rationalizing \: we \: get \\ x = \frac{( \sqrt{5} ) + ( \sqrt{3} )}{( \sqrt{5} ) - ( \sqrt{3)} } \times \frac{( \sqrt{5}) + ( \sqrt{3} )}{( \sqrt{5} ) + ( \sqrt{3}) } \\ \\ = \frac{( \sqrt{ {5} } )^{2} +( \sqrt{3} )^{2} + 2 \times \sqrt{5 \times 3 } }{( \sqrt{5} )^{2} - ( \sqrt{3} )^{2} } \\ \\ = \frac{5 + 3 + 2 \sqrt{15} }{5 - 3} \\ \\ = \frac{8 + 2 \sqrt{15} }{2} \\ \\ = 4 + \sqrt{15} \\ \\ with \: same \: method \\ on \: rationalizing \: the \: value \: of \: y \: w \: get \\ \\ y = \frac{( \sqrt{5} ) - ( \sqrt{3}) }{( \sqrt{5} ) + ( \sqrt{3} )} \times \frac{( \sqrt{5}) + ( \sqrt{3}) }{( \sqrt{5}) + ( \sqrt{3} ) } \\ \\ y = \frac{( \sqrt{5})^{2} + ( \sqrt{3})^{2} - 2 \times \sqrt{5 \times 3} }{( \sqrt{5} )^{2} - ( \sqrt{3})^{2} } \\ \\ y = \frac{5 + 3 - 2 \sqrt{15} }{5 - 3} \\ \\ y = \frac{8 - 2 \sqrt{15} }{2} \\ \\ y = 4 - \sqrt{15}$
Hope my answer would be helpful to you!!!

And if helpful, then please mark as brainliest.

@Mahak24

Thanks...
☺☺