x^5-5x^4+5x^3-1find maximum and minimum values
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Answer:
Let x^3=x
Step-by-step explanation:
according to ques=
x^2-5x+5-1
x^2-5x+4
by quadratic equation =
x^2-4x-x+4
x(x-4)-1 (x-4)
x=1or4
as x^3=s
so, now substituting the x on x^3
x^3=1
x^3=4^3
x^3=64
ans= max. value.=1
min.value= 64
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