Math, asked by rani880083, 17 days ago

(x/5)-5y/6)² Expand it using suitable algebraic Identity​

Answers

Answered by shibanmandi0
0

Answer:

x^2/25-xy/3+25y^2/36.

Step-by-step explanation:

Identity:(a-b)^2=a^2-2ab+b^2

So,

(x/5-5y/6)^2=(x/5)^2-(2×x/5×5y/6)+(5y/6)^2

=x^2/25-xy/3+25y^2/36.

Answered by tennetiraj86
4

Step-by-step explanation:

Given :-

[(x/5)-(5y/6)]²

To find :-

Expand it using suitable algebraic Identity?

Solution :-

Given expression is [(x/5)-(5y/6)]²

This is in the form of (a-b)²

Where

a = x/5

b = 5y/6

We know that

(a-b)² = a²-2ab+b²

=> [(x/5)-(5y/6)]²

=> (x/5)²-2(x/5)(5y/6)+(5y/6)²

=> (x²/25)-[(2x×5y)/(5×6)]+(25y²/36)

=> (x²/25) -(10xy/30)+(25y²/36)

=>(x²/25)-(xy/3)+(25y²/36)

or

The denominators 25,3,36

LCM of 25,3,36 = 900

=> [36x²-300xy+625y²]/900

Answer:-

[(x/5)-(5y/6)]² = (x²/25)-(xy/3)+(25y²/36)

or [36x²-300xy+625y²]/900

Used Identity :-

→(a-b)² = a²-2ab+b²

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