(x/5)-5y/6)² Expand it using suitable algebraic Identity
Answers
Answered by
0
Answer:
x^2/25-xy/3+25y^2/36.
Step-by-step explanation:
Identity:(a-b)^2=a^2-2ab+b^2
So,
(x/5-5y/6)^2=(x/5)^2-(2×x/5×5y/6)+(5y/6)^2
=x^2/25-xy/3+25y^2/36.
Answered by
4
Step-by-step explanation:
Given :-
[(x/5)-(5y/6)]²
To find :-
Expand it using suitable algebraic Identity?
Solution :-
Given expression is [(x/5)-(5y/6)]²
This is in the form of (a-b)²
Where
a = x/5
b = 5y/6
We know that
(a-b)² = a²-2ab+b²
=> [(x/5)-(5y/6)]²
=> (x/5)²-2(x/5)(5y/6)+(5y/6)²
=> (x²/25)-[(2x×5y)/(5×6)]+(25y²/36)
=> (x²/25) -(10xy/30)+(25y²/36)
=>(x²/25)-(xy/3)+(25y²/36)
or
The denominators 25,3,36
LCM of 25,3,36 = 900
=> [36x²-300xy+625y²]/900
Answer:-
[(x/5)-(5y/6)]² = (x²/25)-(xy/3)+(25y²/36)
or [36x²-300xy+625y²]/900
Used Identity :-
→(a-b)² = a²-2ab+b²
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