Question

x=5/6+15/18-10/12, the (x-1)3 is....

Answer 1

x=5/6+15/18-10/12
x=5*3/6*3+15/18-10/12
x=15/18+15/18-10/12
x=30/18-10/12
x=5/3-10/12
x=5*4/3*4-10/12
x=20-10/12
x=10/12
x=5/6

therefore (x-1)^3= (5/6-1)^3
=(5-6/6)^3
=(-1/6)^3
=-1/6*-1/6*-1/6
=-1/216

hope it helps you

Answer 2

The Value of $(x-1)^3$ is $-\frac{1}{216}$

Step-by-step explanation:

Given:

$x = \frac{5}{6} +\frac{15}{18}-\frac{10}{12}$

We need to find $(x-1)^3$

Solution first we will find the value of x by solving the same we get;

we would make the denominator common using LCM we get;

$x = \frac{5\times6}{6\times6} +\frac{15\times2}{18\times2}-\frac{10\times3}{12\times3}\\\\x = \frac{30}{36}+\frac{30}{36}-\frac{30}{36}\\\\x = \frac{30+30-30}{36}\\\\x =\frac{30}{36} =\frac{5\times6}{6\times6} = \frac{5}{6}$

Now $x = \frac{5}{6}$ we will find $(x-1)^3$.

$(x-1)^3 = (\frac{5}{6}-1)^3$

Now we will make the denominator common by LCM.

$(x-1)^3 = (\frac{5\times 1}{6\times 1}-\frac{1\times6}{6})^3\\\\(x-1)^3 = (\frac{5}{6}-\frac{6}{6})^3 = (\frac{5-6}{6})^3 = (-\frac{1}{6})^3\\\\(x-1)^3=-\frac{1}{6}\times -\frac{1}{6}\times -\frac{1}{6} = -\frac{1}{216}$

Hence $(x-1)^3 = -\frac{1}{216}$