Question

) x = 5 + 6coseco, y = 3 + 8coto eliminate theta​

Answer 1

Answer:

[ ( x - 5 ) / 6 ]^2 - [ ( y - 3 ) / 8 ]^2 = 1

Step-by-step explanation:

Given,

x = 5 + 6 cosec$\theta$

x - 5 = 6 cosec$\theta$

( x - 5 ) / 6 = cosec$\theta$

Also,

y = 3 + 8 cot$\theta$

y - 3 = 8 cot$\theta$

( y - 3 ) / 8 = cot$\theta$

From the properties of trigonometry :

• cosec^2 A - cot^2 A= 1

Therefore,

= > cosec^2 $\theta$ - cot^2 $\theta$

= > [ ( x - 5 ) / 6 ]^2 - [ ( y - 3 ) / 8 ]^2 = 1

Eliminated.

Answer 2

Answer:-

• x = 5 + 6 cosec \ thetaθ
• x - 5 = 6 cosec \ thetaθ
• ( x - 5 ) / 6 = cosec \ thetaθ
• y = 3 + 8 cot \ thetaθ
• y - 3 = 8 cot \ thetaθ
• ( y - 3 ) / 8 = cot \ thetaθ
• cosec^2 A - cot^2 A= 1

So,

= cosec^2 \thetaθ - cot^2 \thetaθ

= ( x - 5 ) / 6 )^2 - ( y - 3 ) / 8 )^2 = 1