Question

X + 5 by 6 - X + 1 by 9 is equal to X + 3 by 4​

Answer 1

HEY BUDDY....HERE'S YOUR ANSWER...

$\frac{x + 5}{6 - x} + 1 = \frac{x + 3}{4}$

$\frac{x + 5 + 6 - x}{6 - x} = \frac{x + 3}{4}$

Because we to LCM in the L.H.S side

$\frac{11}{6 - x} = \frac{x + 3}{4}$

$(6 - x)(x + 3) = 11 \times 4$

$6x + 18 - x {}^{2} - 3x = 44$

$- x {}^{2} + 3x + 18 - 44 = 0$

$- {x}^{2} + 3x - 26 = 0$

$- 1(x {}^{2} - 3x + 26) = 0$

$= b {}^{2} - 4ac$

$= ( - 3) {}^{2} - 4(1)(26)$

$= 9 - 94$

=-85

-85<0

So,the equation has imaginary roots.