Math, asked by Rishabh2404, 10 months ago

(x+5) is a factor of (2x4+9x3+6x2-11x-6)

Answers

Answered by nitusingh075
1

Answer:

x= -5

Putting the value of x in the equation,we get

(2(-5)^4+9(-5)^3+6(-5)^2-11(-5)-6)

(2*625+9*(-125)+6*25+55-6)

1250-1125+150+55-6

1455-1131

324

no,x is not a factor.

Step-by-step explanation:

Answered by FamousOne
0

Answer :

No

Step-by-step explanation :

To check whether (x + 5) is a factor of 2x⁴ + 9x³ + 6x² - 11x - 6, we should do the following steps —

Step I : Put (x + 5) equals to zero.

x + 5 = 0

x = - 5

Step II : Put the calculated value of x in the given polynomial.

f(x) = 2x⁴ + 9x³ + 6x² - 11x - 6

f(- 5) = 2(- 5)⁴ + 9(- 5)³ + 6(- 5)² - 11(- 5) - 6

= 2(625) + 9(- 125) + 6(25) - 11(- 5) - 6

= 1250 + (- 1125) + 150 - (- 55) - 6

= 1250 - 1125 + 150 + 55 - 6

= 1250 + 150 + 55 - 1125 - 6

= 1455 - 1131

= 324

Step III : If the answer is zero, then the (x + 5) is a factor, otherwise not.

The answer is 324 ≠ 0.

Hence, (x + 5) is not a factor of given polynomial.

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